0.03*x^2+0.03*x=2

Solution for 0.03*x^2+0.03*x=2 equation:

0.03x^2+0.03x=2

We move all terms to the left:

0.03x^2+0.03x-(2)=0

a = 0.03; b = 0.03; c = -2;
Δ = b2-4ac
Δ = 0.032-4·0.03·(-2)
Δ = 0.2409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.03)-\sqrt{0.2409}}{2*0.03}=\frac{-0.03-\sqrt{0.2409}}{0.06}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.03)+\sqrt{0.2409}}{2*0.03}=\frac{-0.03+\sqrt{0.2409}}{0.06}
$